In an ap if sn n 4n + 1 find the a
WebConsider an arithmetic progression (AP) whose first term is a 1 (or) a and the common difference is d.. The sum of first n terms of an arithmetic progression when the n th term is NOT known is S n = (n/2) [2a + (n - 1) d]; The sum of first n terms of an arithmetic progression when the n th term(a n) is known is S n = n/2[a 1 + a n]; Example: Mr. Kevin … WebIn an AP, if S n=n(4n+1), fill the AP is 5, 13, __, --- Medium Solution Verified by Toppr Correct option is A 21 S n=n(4n+1) ∴S 1=a=1(4+1)=5 and S 2=a 1+a 2=2(4×2+1)=18 ⇒a+a+d=18⇒2a+d=18 ⇒d=18−2a=18−10=8 Therefore the AP is a,a+d,a+2d,.... i.e. 5,13,21,... Was this answer helpful? 0 0 Similar questions In an AP if a=1, a n=20 and S n=399, then n …
In an ap if sn n 4n + 1 find the a
Did you know?
WebCorrect option is A) Given, S n=4n 2−n When n=1 , S 1=4(1) 2−1=4−1=3 Now, obviously, the sum of the first term will be the first term itself, as there are no other terms involved. When n=2 , S 2=4(2) 2−1=16=2=14 The sum of the first 2 terms is equal to a 1+a 2 Therefore, a 1+a 2=14 We have shown, above, that a 1=3 Substituting it in a 1+a 2=14, WebIn an AP, if S n = n (4n + 1), find the AP. Advertisement Remove all ads Solution We know that, the n th term of an AP is a n = S n – S n – 1 a n = n (4n + 1) – (n – 1) {4 (n –1) + 1} …
WebApr 10, 2024 · The Indian Navy has released the official notification 1400 vacancies for the Indian Navy SSR Agniveer Exam 2024. The selection process includes a Computer Based Test, Written Exam & Physical Fitness Test (PFT), and last stage of Medical Examination. Candidates applying for the exam must check the Indian Navy SSR Agniveer Eligibility … WebJan 20, 2014 · In an A.P.,if Sn = n (4n+1) ,find the A.P. Share with your friends 2 Follow 4 Varun.Rawat, Meritnation Expert added an answer, on 21/1/14 We have, S n = 4n 2 + n put n = 1, we get S 1 = 4 (1) 2 + 1 = 4 + 1 = 5 So, First term, a 1 = 5 Put n = 2 , we get S 2 = 4 (2) 2 + 2 = 18 so, a 2 = S 2 - S 1 = 18 - 5 = 13 Put n = 3, we get S 3 = 4 (3) 2 + 3 = 39
Web0001493152-23-011890.txt : 20240412 0001493152-23-011890.hdr.sgml : 20240412 20240411201147 accession number: 0001493152-23-011890 conformed submission type: 8-k public document count: 16 conformed period of report: 20240404 item information: entry into a material definitive agreement item information: regulation fd disclosure item … WebMar 31, 2024 · S n = n (4n + 1) Formula: a = first term d = common difference Calculation: S 1 = 1 (4 × 1 + 1) ⇒ S 1 = 4 + 1 = 5 S 2 = 2 (4 × 2 + 1) ⇒ S 2 = 2 × 9 = 18 Second term = S 2 – …
WebMar 31, 2024 · Best answer Sn=5n2+4n S1=5 (1)^2+4 (1) =5+4 =9 Therefore a1=s1=9 S2=5 (2)^2+4 (2) =5 (4)+8 =28 a2=S2-S1 a2=28-9=19 D=10 A8=a+7d =9+7 (10) =9+70 =79 0 votes answered Apr 1, 2024 by SuhaniKumari (30.9k points) Sum of n natural numbers Sn = 5n2 + 4n Sum of (n - 1) natural numbers 8th term = t8 = 10 x 8 - 1 = 80 - 1 = 79 ← Prev Question …
simplicity\u0027s jzWebFeb 25, 2024 · how this formula is substituted in to the sum plzz explain step wise up to 8n-3 what u r thiking Advertisement Expert-Verified Answer 218 people found it helpful abhi178 … simplicity\u0027s kWebJan 11, 2016 · IN an AP, if sn=n [4n+1] find the AP Asked by archita123 11 Jan, 2016, 06:12: PM Expert Answer Answered by 11 Jan, 2016, 06:22: PM Application Videos This … raymond heights corner brookWebGiven that sn = 4n^2 + 2n. ----- (1) Substitute n = 1 in (1), we get sn = 4(1)^2 + 2(1) = 4 + 2 = 6. So, Sum of the first term of AP is 6 i.e a = 6. Now, Substitute n = 2 in (1), we get sn = 4(2)^2 + 2(2) = 4 * 4 + 2 * 2 = 16 + 4 = 20. So, Sum of the first 2 terms = 20. Now, First-term + second term = 20 6 + a2 = 20 a2 = 20 - 6 a2 = 4. Hence in AP, raymond helbigWeb^ r . c a l v i n McKi n n e y As the result of injuries received a week before, R. Calvin McKinney, a well known resident of near T aney town, died on Thursday morning. Mr. McKinney, who was in his eighty eighth year, sustained a brok en collarbone on Thursday of last week. He had been visiting his son, John McKinney, on the home farm and ... raymond heights petalumaWebMar 29, 2024 · Given Sn = 4n – n2 Taking n = 1 S1 = 4 × 1−12 = 4 – 1 = 3 ∴ Sum of first term of AP is 3 Taking n = 2 in Sn S2 = 4×2−2^2 S2 = 8 – 4 S2 = 4 ∴ Sum of first 2 terms is 4 But … simplicity\u0027s jyWebJan 28, 2024 · In an AP, if Sn = n (4n + 1), find the AP - YouTube #class10#arithmeticprogressionsIn an AP, if Sn = n (4n + 1), find the AP … raymond heintschel obituary